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23y^2-45y=0
a = 23; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·23·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*23}=\frac{0}{46} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*23}=\frac{90}{46} =1+22/23 $
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